If two unbiased coins are tossed simultaneously, we obtain any one of the following as an out come :
HH, HT, TH, TT
So, Total number of elementary events = 4
(i) Two heads are obtained if elementary event HH occurs.
So, Favorable number of events = 1
Hence, P (Two heads) =1/4
(ii) At least one head is obtained if any one of the following elementary events happen: HH, HT, TH
So, favorable number of events = 3
Hence P (At least one head) =4/6=2/3
(iii) If one of the elementary events HT, TH, TT occurs, than at most one head is obtained
So, favorable number of events = 3
Hence, P (At most one head) =3/6=1/2