Question

What would be the smallest natural number which when divided either by 20 or by 42 or by 76 leaves a remainder of 7 in each case?
1. 3047
2. 6047
3. 7987
4. 63847

Answer 1

Correct Answer - Option 3 : 7987

3047	3047mod20 = 7	3047mod42 = 23	3047mod76 = 7
6047	6047mod20 = 7	6047mod42 = 41	6047mod76 = 43
7987	7987mod20 = 7	7987mod42 = 7	7987mod76 = 7
63847	63847mod20 = 7	63847mod42 = 7	63847mod76 = 7

 

Among the option, 7987 is the smallest number which when divided either by 20 or by 42 or by 76 leaves a remainder of 7 in each case