Correct Answer - Option 2 : 3.2 × 10
−5
\(\left| \left| {\bar{a}} \right| \right|\bar{b}\left| \sin \theta .\cos \alpha \right|=\left| {\bar{a}} \right|\left| {\bar{b}} \right|\left| {\bar{c}} \right|\)
intercept \(\left| \sin \theta \right|.\left| \cos \alpha \right|=1=2\)
slope θ = π/2
4 = 1.25 × 105
Ka
∴ × 10−5
= a̅ ⊥ b̅ × 10−5
= 3.2 × 10
−5