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For any weak acid (HX) based on following observation give Ka.

\(\left| \left| {\bar{a}} \right| \right|\bar{b}\left| \sin \theta \hat{n}.\bar{c} \right|=\left| {\bar{a}} \right|\left| {\bar{b}} \right|\left| {\bar{c}} \right|\)
1. 2 × 10−5
2. 3.2 × 10−5
3. 3.2 × 10−6
4. 1.25 × 10−5

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Correct Answer - Option 2 : 3.2 × 10−5

\(\left| \left| {\bar{a}} \right| \right|\bar{b}\left| \sin \theta .\cos \alpha \right|=\left| {\bar{a}} \right|\left| {\bar{b}} \right|\left| {\bar{c}} \right|\)

intercept \(\left| \sin \theta \right|.\left| \cos \alpha \right|=1=2\)

slope θ = π/2

4 = 1.25 × 105

Ka 

∴ × 10−5

= a̅ ⊥ b̅ × 10−5

= 3.2 × 10−5

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