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Calculate the oxidation number of the underlined atom.

H2SO4

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H2SO4

Oxidation number of H = +1

Oxidation number of O = −2

H2SO4 is a neutral molecule.

∴ Sum of the oxidation numbers of all atoms of H2SO4 = 0

∴ 2 × (Oxidation number of H) + (Oxidation number of S) + 4 × (Oxidation number of O) = 0

∴ 2 × (+1) + (Oxidation number of S) + 4 × (–2) = 0

∴ Oxidation number of S + 2 – 8 = 0

∴ Oxidation number of S in H2SO4 = +6

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