Confining pressure = σ3 = 100 kPa
Deviator stress = σ1 – σ3 = 80 kPa
σ1 = 80 + σ3 = 180 kPa
Pore pressure = u = 50 kPa
\({\bar \sigma _1} = {\sigma _1} - u\)
= 180 – 50 = 130 kPa
\({\bar \sigma _3} = {\sigma _3} - u\)
= 100 – 50 = 50 kPa
For NC soil C’ = 0
\(\begin{array}{l} {{\bar \sigma }_1} = {{\bar \sigma }_3}\left( {\frac{{1 + \sin \phi }}{{1 - \sin \phi }}} \right)\\ 130 = 50\left( {\frac{{1 + \sin \phi }}{{1 - \sin \phi }}} \right)\\ \sin \phi = \frac{8}{{18}} \end{array}\)
ϕ = 26.4°