Correct Answer - Option 4 : 0.01 A
\({I_s} = \frac{{{E_s}}}{{{R_s}}} = \frac{{22}}{{220}} = 0.1\;A\)
For an ideal transformer
\(\frac{{{I_p}}}{{{I_s}}} = \frac{{{E_s}}}{{{E_p}}} = \frac{{{N_s}}}{{{N_p}}} \Rightarrow {I_p} = \frac{{{E_s}}}{{{E_p}}} \times {I_s} = \frac{{22}}{{220}} \times 0.1 = {10^{ - 2}}A\)