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A 2.5 litre flask contains 0.5 mole each of sulphur dioxide and nitrogen gas at 127° C. Calculate the pressure exerted by sulphur dioxide.


1. 6.65 × 105 Pa
2. 2.49 × 105 Pa
3. 9.14 × 105 Pa
4. 7.2 × 105 Pa

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Correct Answer - Option 1 : 6.65 × 105 Pa

From the Dalton’s Law

Partial pressure of SO2

PSO2 = nRT / V = 0.5 × 8.314 × 400 / 2.5 × 10–3 = 6.65 × 105 Nm–2 = 6.65 × 105 Pa

Similarly PN2 = 2.49 × 105 Pa

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