Correct Answer - Option 1 : [ML
3T
-1Q
-2]
Specific resistance, \(\rho = \frac{{WAt}}{{{q^2}l}}\)
Now, putting dimensions of each term, we get \(\left[ \rho \right] = \frac{{\left[ {M{L^2}{T^{ - 2}}} \right]\left[ {{L^2}} \right]\left[ T \right]}}{{[{Q^2}]\left[ L \right]}}\)
We get,
\(\rho = \left[ {M{L^3}{T^{ - 1}}{Q^{ - 2}}} \right]\)