Correct Answer - Option 2 : 166.5
Concept
The force transmitted by the gear is given by,
\({F_t} = \frac{{{\sigma _b} \times b \times Y \times m}}{{{f_s}}}\)
where σb = Minimum allowable stress for gear material
Y = Tooth geometry factor
fs Combined effect of dynamic load and allied factors intensifying the stress.
b = Face width of the tooth
m = Module of the gear
Calculation:
Given:
Tooth geometry factor, Y = 0.32
The combined effect of dynamic load and allied factors intensifying the stress, fs = 1.5
Face width of the tooth, b = 25 mm
The module of the gear, m = 4 mm
Force transmitted,
\({F_t} = \frac{{{\sigma _b} \times b \times Y \times m}}{{{f_s}}}\)
\(3552 = {\rm{}}\frac{{{\sigma _b} \times 25 \times 0.32 \times 4}}{{1.5}}\)
σ b = 166.5 MPa