Correct Answer - Option 2 : At least one system is unstable and at least one system is causal
Let three LTI systems have response H1 (z), H2 (z) and H3 (z) are cascaded as shown fellow
\(\frac{i}{p} \to \boxed{{H_1}\left( z \right)} \to \boxed{{H_2}\left( z \right)} \to \boxed{{H_3}\left( z \right)} \to H\left( z \right)\)
Assume H1 (z) = z2 +z1+1 (non-casual)
H2 (z) = z3 +z2+1 (non-casual)
Overall response of the system
H (z) = H1(z) H2(z) H3(z)
= (z2+z1+1) (z3+z2+1) H3(z)
To make H(z) causal we have to take H3(z) also causal.
Let H3(z) =z-6+z-4+1
H(z) =(z2+z+1) (z3+z2+1) (z-6+z-4+1)
H(z) → causal
Similarly, to make H(z) unstable at least one of the system should be unstable.