Correct Answer - Option 2 : 50%
Concept:
Let ‘P’ be the atmospheric pressure in (kPa)
‘ϕ’ be the relative humidity, ‘Pv’ be the partial pressure of the air in (kPa), ‘Pvs’ be the saturation pressure of water in (kPa), ‘ω’ be the specific humidity of air in (kg/kg of dry air).
\(ϕ = \frac{{{P_v}}}{{{P_{vs}}}} \)
\(ω = 0.622\;\times\frac{{{P_v}}}{{\left( {P\ - \ {P_v}} \right)}} \)
Given:
Calculation:
Pv = 1.5 kPa, Pvs = 3 kPa
\(ϕ = \frac{{{P_{v}}}}{{{P_{vs}}}} \)
\(\Rightarrow ϕ = \frac{{1.5}}{{{3}}}\)
ϕ = 50%