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If \(\int_{-1}^{1}f(x)dx= 0 \) then
1. f(x) = f(-x)
2. f(-x) = -f(x)
3. f(x) = 2f(x)
4. None of these

1 Answer

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Best answer
Correct Answer - Option 2 : f(-x) = -f(x)

Concept:

1. The rules for integrating even and odd functions:

If the function is even or odd and the interval is [-a, a], we can apply these rules:

  • When f(x) is even ⇔ \(\mathop \smallint \nolimits_{ - a}^a f\left( x \right)dx = 2\mathop \smallint \nolimits_0^a f\left( x \right)dx{\rm{\;}}\)
  • When f(x) is odd ⇔ \(\mathop \smallint \nolimits_{ - a}^a f\left( x \right)dx = 0\)


2. If f is even then f (-x) = f (x)

3. If f is odd then f (-x) = -f (x)

Calculation:

Given that

\(\int_{-1}^{1}f(x)dx= 0 \)

According to the fundamental property discussed above, this will be possible only if

f(-x) = -f(x)

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