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when the shadow of a pole of 10 m height is 10√3 m, angular elevation of the Sun is:
1. 60°
2. 90°
3. 75°
4. 30°

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Correct Answer - Option 4 : 30°

Given:

The shadow of a pole of 10 m height = 10√3 m

Calculation:

Let the angular elevation of sun = θ 

tanθ = Perpendicular/Base

⇒ tanθ = 10/10√3

⇒ tanθ = 1/√3

⇒ tanθ = tan 30° 

⇒ θ = 30° 

∴ The angular elevation of the sun is 30° 

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