Correct Answer - Option 2 : 90,00,000
Concept:
While excavating the soil from the borrow pit and after that compacting it, the mass of solids and its specific gravity will not change, and hence, the volume of solids remains constant even after compaction.
The Total volume(V) of soil is given by
V = Vv + Vs ...........(i)
Where V = Total volume of soil, Vv = Volume of voids, Vs = Volume of solids
Divide the equation (i) by Vs (Volume of solids)
\({V \over V_s} = {V_v \over V_s}+ {V_s \over V_s}\)
\({V \over V_s} = {V_v \over V_s}+ 1\)
\({V \over V_s} = e+ 1\)
\({ V_s} = {V \over(1+e)}\)
Calculation:
Condition - I: Filling
ef = 0.7 and Vf = 8,50,000 m3
So, Volume of solids in filling(Vsf)
\({ V_{sf}} = {V_f \over(1+e_f)} = {850000 \over(1+0.7)}\) = 500000 m3
Condition-I: Excavation
The volume of solids will be the same as that of during fill i.e. Vsf = 500000 m3
eexc = 0.8
So, find the volume of excavated soil(Vexc)
\({ V_{s(exc)}} = {V_{exc} \over(1+e_{exc})} \)
\(500000 = {V_{exc} \over(1+0.8)} \)
\(V_{exc} = {500000 \times (1+0.8)} \) = 900000 m3
The estimated cost for the filling work is (in Rs.) = 10 \(\times\) 900000 = 90,00,000