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H.C.F of 143 and 481 is 143m + 481n, then m, n are equal to:
1. -9, 3
2. -8, 3
3. -10, 3
4. -7, 3

1 Answer

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Correct Answer - Option 3 : -10, 3

Given:

H.C.F of 143 and 481 is 143m + 481n

The highest common factors among the given numbers are defined as the HCF of that numbers.

Calculation:

Using factorization, HCF can be found as

143 = 11 × 13

481 = 37 × 13

HCF = 13

The given HCF 143m + 481n

So equating both HCF, we get as

143 m + 481n = 13

⇒ 13 (11m + 37n ) = 13

⇒ (11m + 37n ) = 1     ---(i)

Now substituting all values, the options that satisfies the above equation will be the final answer.

Using option 3 as (-10, 3)

m = -10

n = -3

From equation (i)

11 × (-10) + 37 × (-3) = 1, which satisfies.

So, final answer is  -10, 3

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