Correct Answer - Option 2 : 800/π
Concept:
Strength of the Solid Shaft of Circular Cross-Section
\(T = {\pi\over 16}\times τ ×D^3 \)
where T = Turning force or torque, τ = Maximum shear stress and D = Diameter of the cross-section.
Calculation:
Given:
T = 3200 N-m = 3200 × 103 N-mm, D = 40 mm, and τ = ?
\(T = {\pi\over 16}\times τ ×D^3 \)
\(3200\times 10^3 = {\pi\over 16}\times τ ×40^3 \)
\(\tau = \frac{800}{\pi}\)
