Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
192 views
in Aptitude by (111k points)
closed by
If \(\frac{√11 - 3}{√ 11 + 3} \) =  a√11 + b, then find the value of (a + b)2
1. 49/4
2. 49
3. 169
4. 169/9

1 Answer

0 votes
by (105k points)
selected by
 
Best answer
Correct Answer - Option 2 : 49

Given:

 \(\frac{√11 - 3}{√ 11 + 3} \) =  a√11 + b

Formula used:

(a + b)2 = a2 + b2 + 2ab

(a + b)(a - b) = a2 - b2

Calculation:

Take L.H.S

\(\frac{√11 - 3}{√ 11 + 3} \)

Rationalisation above the equation

⇒ \(\frac{(√11 - 3) \;\times\;(√11 - 3) }{(√ 11 + 3)\; \times\;(√11 - 3)} \)

⇒ (√11 - 3)2/(11 - 9)

⇒ (11 + 9 - 6√11)/2

⇒ (20 - 6√11)/2

⇒ 10 - 3√11

Compare the above term with (a√11 + b), we get 

a = - 3 and b = 10

⇒ (a + b)2 = {-3 + 10}2

⇒ (7)2

⇒ 49

∴ The required value of (a + b)2 is 49.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...