Correct Answer - Option 5 : x = y or relationship between x and y cannot be established
Given:
x2 + x – 210 = 0
y2 + 3y – 130 = 0
Calculation:
From I,
x2 + x – 210 = 0
⇒ x2 + 15x – 14x – 210 = 0
⇒ x(x + 15) – 14(x + 15) = 0
⇒ (x + 15)(x – 14) = 0
⇒ x = -15, 14
From II,
y2 + 3y – 130 = 0
⇒ y2 + 13y – 10y – 130 = 0
⇒ y(y + 13) – 10(y + 13) = 0
⇒ (y + 13)(y – 10) = 0
⇒ y = -13, 10
Comparison between x and y (via Tabulation):
Value of x
|
Value of y
|
Relation
|
-15
|
-13
|
x < y
|
-15
|
10
|
x < y
|
14
|
-13
|
x > y
|
14
|
10
|
x > y
|
∴ The relationship between x and y cannot be established.