Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
602 views
in Chemistry by (1.5k points)

Please log in or register to answer this question.

1 Answer

0 votes
by (7.2k points)

KOH is a beta eliminating agent. If we dehydrogenate the compound with KOH then the major product will be 2, 2 dimethyl but-3-ene.

As there is no beta hydrogen atom at the 2 2 dimethyl position.
 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...