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Two identical coherent waves of intensity Io are superimposed at a point. If the resultant intensity at this point is three times of Io then find the phase difference between the two waves at this point.
1. \(\frac{\pi}{6}\)
2. \(\frac{\pi}{4}\)
3. \(\frac{\pi}{3}\)
4. None of these

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Correct Answer - Option 3 : \(\frac{\pi}{3}\)

CONCEPT:

Coherent addition of waves:

  • The phenomenon in which two or more waves superpose to form a resultant wave of greater, lower, or the same amplitude is called interference.
  • The interference is based on the superposition principle according to which at a particular point in the medium, the resultant displacement produced by a number of waves is the vector sum of the displacements produced by each of the waves.
  • Let two sources of wave S1 and S2 are coherent.
  • Let the intensity of the waves are Io.

For constructive interference:

  • If at any point the waves emerging from the two coherent sources S1 and S2 are in phase then we will have constructive interference and the resultant intensity will be 4Io.

⇒ Path difference = nλ and n = 0,1,2,3,...

For destructive interference:

  • If at any point the waves emerging from the two coherent sources S1 and S2 are in opposite phase then we will have destructive interference and the resultant intensity will be zero.

⇒ Path difference = \(\left ( n+\frac{1}{2} \right )\)λ and n = 0,1,2,3,...

Where λ = wavelength

  • Let at any point the phase difference between the displacements of the two waves is ϕ.
  • So the displacement of the two waves is given as,

⇒ y1 = a.cos(ωt)

⇒ y2 = a.cos(ωt + ϕ)

  • When the waves are superimposed at this point the resultant displacement is given as,

\(⇒ y=2acos\left ( \frac{ϕ}{2} \right )cos\left ( \omega t+ \frac{ϕ}{2} \right )\)

  • The amplitude of the resultant displacement is given as,

\(⇒ A=2acos\left ( \frac{ϕ}{2} \right )\)

  • The intensity at that point is given as,

\(⇒ I=4I_ocos^2\left ( \frac{ϕ}{2} \right )\)

EXPLANATION:

Given Intensity = Io, and Resultant intensity I = 3Io

The resultant intensity at that point is given as,

\(⇒ I=4I_ocos^2\left ( \frac{ϕ}{2} \right )\)

\(⇒ 3I_o=4I_ocos^2\left ( \frac{ϕ}{2} \right )\)

\(⇒ cos\left ( \frac{ϕ}{2} \right )=\frac{\sqrt3}{2}\)

\(⇒ \frac{ϕ}{2}=\frac{\pi}{6}\)

\(⇒ ϕ=\frac{\pi}{3}\)

  • ​Hence, option 3 is correct.

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