Correct Answer - Option 1 : (9/10)
th
Given:
Pipe A can fill a tank = 3 hours
Pipe B can fill a tank = 5 hours
Pipe C can empty a tank = 12 hours
Calculation:
Total capacity of the tank = 60 units (L.C.M of 3, 5 and 12)
Pipe A filled tank in 1 hour = 60/3
⇒ 20 units
Pipe B filled a tank in 1 hour = 60/5
⇒ 12 units
Pipe C empty a tank in 1 hour = 60/12
⇒ 5 units
Tank filled in 1 hour = 20 + 12 - 5
⇒ 27 units
Tank filled in 2 hour = 27 × 2
⇒ 54 units
Portion of tank filled in 2 hours = (54/60)
⇒ (9/10)th
∴ (9/10)th of a tank is filled in 2 hours.