Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
747 views
in Parabola by (114k points)
closed by
The conic: 16x2 - 24xy + 9y2 - 104x - 172y + 44 = 0 represents a:
1. hyperbola
2. ellipse
3. circle
4. parabola

1 Answer

0 votes
by (113k points)
selected by
 
Best answer
Correct Answer - Option 4 : parabola

Concept:

The general equation of conics of a second degree is given by:\(a{x^2} + 2hxy + b{y^2} + 2gx + 2fy + c = 0\) 

and discriminant

Δ = abc + 2fgh – af2 – bg2 – ch2.

The above given equation represents a non-degenerate conics whose nature is given below in the table:

S.No

Condition

Nature of Conic

1

Δ ≠ 0, h = 0, a = b, e = 0

Circle

2

Δ ≠ 0, h2 – ab = 0, e = 1

Parabola

3

Δ ≠ 0, h2 – ab < 0, e < 1

Ellipse

4

Δ ≠ 0, h2 – ab > 0, e > 1

Hyperbola

5

Δ ≠ 0, h2 – ab > 0, a + b = 0, e = 1/2

Rectangular Hyperbola

 

Calculation:

The equation 

16x2 - 24xy + 9y2 - 104x - 172y + 44 = 0

a = 16, b = 9, h = -12, g = = - 52, f = - 86, c = 44

∵ Δ = abc - 2fgh - af2 - bg2 - ch2

⇒ Δ = 16.9.44 - 2.(-86)(-52)(-12) - 16.(-86)2 - 9.(-52)2 - 44(-12)2

⇒ Δ = 6336 + 107328 - 118336 - 24336 - 6336

⇒ Δ = - 35344 ≠ 0

h2 - ab  = (-12)2 - 16.9

⇒ h2 - ab = 0

As dicsueed above, we know that, 

if Δ ≠ 0 and h2 - ab = 0 it represents parabola.

Hence, given equation reprtesents parabola.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...