Correct Answer - Option 2 : 1
Given :
Expression is x4 – 2x2 + k
Formula Used :
A quadratic expression ax2 + bx + c, a ≠ 0 is a perfect square, when
b2 - 4ac = 0
Calculation :
Given expression is x4 – 2x2 + k
⇒ (x2)2 - 2x2 + k
Let the value of x2 be y
⇒ y2 - 2y + k
On comparing quadratic expression we get a = 1, b = -2 and c = k
According to the question, this expression is a perfect square
⇒ b2 - 4ac = 0
⇒ (-2)2 - 4 × 1 × k = 0
⇒ 4 - 4k = 0
⇒ k = 1
∴ The value of k is 1.