Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
69 views
in General by (114k points)
closed by
If temperature will increase, the conductivity of semiconductor will:
1. remains the same
2. decrease
3. decrease rapidly
4. increase

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 4 : increase

Explanation:

Current in a material can be expressed as:

I = NqAvd

Where

N = Carrier concentration

q = electrons charge (magnitude)

A = cross-section area

The current density (J) will be:

\(J = \frac{I}{A} = Nq{v_d}\)    ---(1)

Also, J = σ E     ----(2)

σ = conductivity

E = Electric field

J = Current density

vd = μ E    ----(3)

μ = mobility of carriers

E = Electric field

Analysis:

On using equation (1), (2) & (3) we get,

J = NqVd = NqμE = σE

⇒ σ = Nqμ  

So as conductivity is directly proportional to the mobility of ions and the number of EH pair ions.

The conductivity of an intrinsic semiconductor depends upon the number of hole electron pairs and mobility. The number of hole electron pairs increases with an increase in temperature, while its mobility decreases. However, the increase in hole electron pairs is greater than the decrease in their mobility.

So with an increase in temperature, conductivity in semiconductors also increases.

Hence option (4) is the correct answer.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...