Correct Answer - Option 1 : 144
Given
Standard deviation σ = 2 cm
z = 2.58 for 99% confident level
Formula
Standard error = σ/√n
Calculation
SE= σ/√n
⇒ 2.58 × σ/√n ≤ 0.43 here z = 2.58
⇒ √n = (2.58 × 2)/0.43
⇒ √n = 12
⇒ n = 144
∴ The size of the sample in order to be 99% confident that the error of her estimates of mean does not exceed 0.43 cm is 144