Correct Answer - Option 2 : 49 ∶ 1
Concept:
The maximum intensity of interference of two waves of intensities I1 and I2 is given as
\(I_{max} = (\sqrt{{I_1}} + \sqrt{{I_2}})^2\)
The minimum intensity of interference of two waves of intensities I1 and I2 is given as
\(I_{min} =( \sqrt{{I_1}} - \sqrt{{I_2}})^2\)
Calculation:
Given intensities rato is 16 : 9
We can say that
\(\frac{I_1}{I_2} = \frac{16}{9}\)
\(\implies \sqrt{ \frac{I_1}{I_2}} = \sqrt \frac{16}{9} = \frac{4}{3}\)
So,
\(I_{max} =({ \sqrt{{16}} + \sqrt{{9}} })^2= 7^2 =49\)
\(I_{min} =( \sqrt{{16}} - \sqrt{{9}} )^2= 1\)
So, the ratio is
I max : I min = 49 : 1
The correct option is 49 : 1
