Correct Answer - Option 1 : 5 : 4

**Given:**

Alloy A contains copper and zinc in the ratio 5 : 2

Alloy B contains copper and zinc in the ratio 3 : 4

Alloy C is prepared by mixing A and B in the ratio 4 : 5

**Calculations:**

Alloy A,

⇒ Copper = 5/7, Zinc = 2/7

Alloy B,

⇒ Copper = 3/7, Zinc = 4/7

A and B taken in the 4 : 5 Ratio

Let A be 4x and B be 5x,

In mixture C,

Copper = (5/7)4x + (3/7)5x = 35x/7

Zinc = (2/7)4x + (4/7)5x = 28x/7

Ratio of Copper to Zinc in mixture C,

⇒ 35x/7 : 28x/7

⇒ 5 : 4

**∴**** Ratio of Copper to Zinc is 5 : 4.**