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The radius of the circle 2x2 + 2y2 + 24x + 24y + 8 = 0 is
1. 2√14
2. 2√17
3. 3√11
4. 3√14

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Correct Answer - Option 2 : 2√17

Concept:

The general second degree equation of a circle in x and y is given by:  x2 + y2 + 2gx + 2fy + c = 0 with centre (-g, -f) and radius

 \(\rm r = \sqrt {{g^2} + {f^2} - c} \)

 

Calculation:

Given:   2x2 + 2y2 + 24x + 24y + 8 = 0 

⇒ 2 (x2 + y2 + 12x + 12y + 4) = 0

⇒ x2 + y2 + 12x + 12y + 4 = 0 are equation of circle with centres C and radius r 

By comparing the equation of the circle with the equation  x 2 + y2 + 2gx + 2fy + c = 0 we get 

g = 6, f =  6 and c = 4

As we know, radius = \(\rm r = \sqrt {{g^2} + {f^2} - c} \)

\(\rm r = \sqrt {{36} + {36} - 4} \)

r = 2√17 unit

∴ The radius of circle is 2√17

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