Correct Answer - Option 4 : 4.9 kΩ
Concept:
To increase the range of a voltmeter, we need to the series resistance and it is given by
\({R_{se}} = {R_m}\left( {\frac{V}{{{V_m}}} - 1} \right)\)
Where V is the required voltmeter range
Vm is the voltmeter range
Rm is the meter internal resistance
Calculation:
Given that,
Meter full scale current reading (Im) = 10 mA
Internal resistance (Rm) = 100 Ω
Voltmeter range (Vm) = I m Rm = 10 × 10-3 × 100 = 1.0 V
Required voltmeter range (V) = 50 V
\({R_{se}} = 100\left( {\frac{{50}}{1} - 1} \right) = 4.9k\;{\rm{Ω }}\)