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R.L. of point ‘A’ is 50 m and R.L. of point ‘B’ is 46.655 m. The distance between AB is 150 m. The gradient of line AB is
1. 1 in 67.26 (Rising)
2. 1 in 44.84 (Falling)
3. 1 in 30.00 (Rising)
4. 1 in 30.00 (Falling)

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Correct Answer - Option 2 : 1 in 44.84 (Falling)

Concept:

Reduced level: 

The height of any point with respect to mean sea level is known as reduced level.

Gradient:

Gradient describes the slope or steepness of the line joining two points. The gradient of a line is determined by the ratio of the vertical changes to horizontal changes. 

Gradient = \(\tan {\rm{\theta }} = \frac{h}{{L}}\)

Where, h = Change in the elevation of two points
L = Horizontal distance between two points.

Calculation:

Given, Distance between AB (L)= 150 m

R.L. of point ‘A’ = 50 m and R.L. of point ‘B’ = 46.655 m

The difference in the elevation of AB (h)= 50 - 46.655 = 3.345 m

Gradient = \(\tan {\rm{\theta }} = \frac{h}{{L}}\)

Gradient = \( \frac{3.345}{{150}}\)

Gradient = \( \frac{1}{{44.843}}\)

The elevation of point B is less than point A. So the gradient of AB is falling.

Gradient = \( \frac{1}{{44.843}}\)(Falling).

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