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Find the H.C.F of (6/5), (1/3) and (2/7)
1. 3/79
2. 1/105
3. 5/607
4. 1/17

1 Answer

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Best answer
Correct Answer - Option 2 : 1/105

Given

(6/5), (1/3) and (2/7)

Concept

H.C.F of fraction = (H.C.F of numerator)/(L.C.M of denominator)

Calculation

H.C.F = H.C.F of 6, 1 and 2/L.C.M of 5,3 and 7

H.C.F = 1/105

 

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