Correct Answer - Option 1 :
\(\frac{3}{5} \)
Concept:
Degree of Reaction
\(R = \frac{{enthalpy\;drop\;in\;moving\;blade}}{{Total\;enthalpy\;drop}}\)
It indicates how much enthalpy drop is taking place in the rotor of the turbine.
Calculation:
Given:
Enthalpy drop in moving blade = 30 kJ/kg,
Enthalpy drop in fixed blade = 20 kJ/kg,
Total Enthalpy drop = Enthalpy drop in moving blade + Enthalpy drop in fixed blade = 50 kJ/kg
\(R = \frac {30}{30+20} = \frac{3}{5}\)