Correct Answer - Option 2 :
\(\rm B_2 H_6 \ + \ Excess \ NH_3 \ \xrightarrow{ \ \ \Delta \ \ }\)
Concept:
- Boranes are the analogous series of hydrides of boron.
- About 25 neutral boranes and a large number of borane anions are known at present. The neutral boranes mostly belong to either of the two following general classes:
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Nido boranes: B2H6, B5H9
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Arachno boranes: B4H10, B5H11
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Nido boranes: B8H12, B10H14B6H10
- Boranes are prepared via the following reaction:
B2H6 (180 - 220)0C → B5H9 + B10H14
- Electrophilic substitution reactions of borane are also known. B5H9 undergoes Friedel-Crafts alkylation to give 1-alkyl derivatives.
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Electrophilic substitution by halogens is also known.
Explanation:
Aminoboranes:
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Aminoboranes contain B-N bonds in which the boron is trigonally hybridized.
- The lone pair on nitrogen may be donated to a vacant p orbital on boron, giving rise to B-N bond order greater than one.
- Aminoboranes are prototypes of alkenes.
- Aminoboranes can be prepared from amine and boranes.
- The reaction of diborane with ammonia gives borazines. the reaction is:
3B2H6 + 2NH3 → 2B3N3H6+ 12H2
- When reacted with excess NH3, the reaction is:
B2H6 + Excess NH3 → (BN)x + H2
- The reaction takes place at high temperatures with the evolution of hydrogen.
Hence, we can prepare (BN)x from B2H6 by the reaction B2H6 + Excess NH3 → (BN)x