Correct Answer - Option 2 : 0.3
Concept:
Discharge through rectangular notch
\(Q = \frac{2}{3}{c_d}.b\sqrt {2g} {\left( H \right)^{3/2}}\)
Where,
H = Height of water above will of notch
b = width of the notch
Cd = coefficient of discharge
\(\therefore dQ = \frac{2}{3}{C_d}b\sqrt {2g} \times \frac{3}{2}{\left( H \right)^{1/2}}dH\)
\(dQ = \left( {\frac{2}{3}{C_d}b\sqrt {2g} \times {H^{\frac{1}{2}}} \times H} \right) \times \frac{3}{2}\frac{{dH}}{H}\)
\(dQ = Q \times \frac{3}{2}\frac{{dH}}{H}\)
\(\frac{{dQ}}{Q} = \frac{3}{2}\frac{{dH}}{H}\)
Calculation:
\(\frac{{dQ}}{Q} = \frac{3}{2}\times\frac{{1.5}}{750} = 0.3\)%