Correct Answer - Option 3 : Rs. 4944.5
Given:
P = Rs. 7500
R = 10%
N = 3 Years
Amount paid back at end of year 1 = Rs. 2800
Amount paid back at end of year 2 = Rs. 1500
Formula used:
A = P × {1 + (R / 100)}N
Where P = Principal amount, R = Rate of interest in %, N = Number of years
A = P + I
Calculation:
Amount to be paid at end of 1st year = 7500 × {1 + (10 / 100)}
⇒ A = 8250
She pays Rs. 2800 at end of 1st year
⇒ Amount left = 8250 – 2800
⇒ Amount left = 5450
Amount at end of 2nd year = 5450 × {1 + (10 / 100)}
⇒ Amount at end of 2nd year = 5995
She paid Rs. 1500 at the end of 2nd year
⇒ Amount left to pay = (5995 – 1500)
⇒ Amount left to pay at end of 2nd year = Rs. 4495
Amount at end of 3rd year = 4495 × {1 + (10 / 100)}
⇒ Amount at end of 3rd year = 4944.5
∴ At the end of year 3 she need to pay Rs. 4944.5 to clear all her dues.