Correct Answer - Option 4 : 1
Given:
tan24.tan48.tan42.tan66
Formula used:
tanθ = cot(90 – θ)
tanθ = 1/(cotθ)
Calculation:
tan48 = cot(90 – 48) = cot42
tan66 = cot (90 – 66) = cot24
Now we have
tan24.cot24.tan42.cot42
⇒ tan24.(1/tan24).tan42.(1/tan42) = 1
∴ The value of tan24.tan48.tan42.tan66 is 1.
