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If main memory access time is 400 μs, TLB access time is 50 μs, considering TLB hit as 90%, what will be the overall access time?  
1. 800 μs 
2. 490 μs
3. 485 μs
4. 450 μs

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Correct Answer - Option 2 : 490 μs

Data:

TLB hit ratio = p = 90% = 0.9

TLB access time = t = 50 μs

Memory access time = m = 400 μs

Effective memory acess time = EMAT

Formula:

EMAT = p × (t + m) + (1 – p) × (t + m + m)

Calculation:

EMAT = 0.9 × (50 + 400) + (1 – 0.9) × (50 + 400 + 400)

EMAT = 490 μs

∴ the overall access time is 490 μs

During TLB hit

Frame number is fetched from the TLB (50 μs)

and page is fetched from physical memory (400 μs)

During TLB miss

TLB no entry matches (50 μs)

Frame number is fetched from the physical memory (400 μs)

and pages are fetched from physical memory (400 μs)

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