Correct Answer - Option 3 : 2 : 3

**Concept:**

**Electric Power:**

- The rate of consumption of electrical energy is called Electric power.
- It is given as

\(P = \frac{V^2}{R}\)

If the Potential difference is constant, Power is inversely proportional to resistance.

\(\implies P \propto \frac{1}{R}\) or

Power × Resistance is constant

**Calculation:**

Now, Power of resistance 1 (R_{1}) = P_{1} = 60 W

Now, Power of resistance 2 (R2) = P2 = 40 W

Now, P_{1} R_{1} = P_{2}. R_{2}

\(\implies \frac{R_1}{R_2} = \frac{P_2}{P_1}\)

\(\implies \frac{R_1}{R_2} = \frac{40}{60} = \frac{2}{3}\)

So, the required ratio is 2 : 3

The power in terms of current and resistance is given as

P = I ^{2} R

I is current

So, If the **current would have been constant, **the power would have been **directly proportional to resistance.**