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A machine gun fires a bullet of mass 40 g with velocity 1200 m/s. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?
1. 6
2. 3
3. 48
4. 1

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Correct Answer - Option 2 : 3

The correct answer is option 2) i.e. 3

CONCEPT:

  • Linear momentum: Linear momentum is the impact caused due to a body in translational motion.
    • The greater the mass and velocity of the moving body the more will be the impact and thus greater the momentum.
    • The linear momentum of a moving object is defined mathematically as:

⇒ p = mv

​Where p is the linear momentum, m is the mass of the object, and v is the velocity of the object.

  • From Newton's second law of motion, the rate of change of momentum is directly proportional to the force applied by the moving body. 

⇒ dp/dt ∝ F

\(⇒ \frac{dp}{dt} = \frac{d(mv)}{dt} = m\frac{dv}{dt} = ma =F\)

CALCULATION:

Given that:

Mass of each bullet, m = 40 g = 0.04 kg

Velocity of the bullet, v = 1200 m/s

Let N be the number of bullets fired in each second (\(\frac{N}{1\: s}\))

When N bullets are fired per second, the total force that can be exerted on the gun, F = 144 N

The momentum of N bullets, p = N(mv)

From Newton's second law of motion,

\(⇒ \frac{d(Nmv)}{dt} = m\times v \times\frac{N}{t} =F \)

\(⇒ 0.04\times1200\times \frac{N}{1}=144\)  (∵ t = 1 s)

N = 3

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