Correct Answer - Option 5 : 60 km/hr
Let the original time taken by Surbhi to reach point B from point A = t hours
Then, original time taken by Pragati to reach point B from point A = (t – 1.5) hours
Also, let original speed of Pragati = v km/hr
So, the distance between point A and B = v × (t – 1.5) = (v – 6) × (t – 1) = 45t ---- (1)
\Rightarrow v/(v – 6) = (t – 1)/(t – 1.5)
\Rightarrow v/6 = (t – 1)/0.5 {applying a/b = c/d \Rightarrow a/(a – b) = c/(c – d)}
\Rightarrow v = 12(t – 1) ---- (2)
From eq. (1) and eq. (2)
\Rightarrow 12(t – 1)(t – 1.5) = 45t
\Rightarrow 4(t2 – 2.5t +1.5) = 15t
\Rightarrow 4t2 – 10t + 6 = 15t
\Rightarrow 4t2 – 25t + 6 = 0
\Rightarrow 4t2 – 24t - t + 6 = 0
\Rightarrow 4t(t – 6) – (t – 6) = 0
\Rightarrow (4t – 1)(t – 6) = 0
\Rightarrow t = ¼ or t = 6
Since t > 1, so t = ¼ not possible, thus t = 6
\Rightarrow v = 12(6 – 1) = 60 km/hr