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A magnetic material has a magnetization of 2350 A/m and produces a flux density of 3.142 mWb/m2. Then, the relative permeability of the material is:
1. 11.67
2. 17.47
3. 12.47
4. 16.67

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Correct Answer - Option 4 : 16.67

Concept:

Magnetic field strength or field intensity (H) is the amount of magnetizing force.

Magnetic flux density (B) is the amount of magnetic force induced on the given body due to the magnetizing force H.

The relation between B and H is,

B = μH

Where, 

μ = μ0 μr =  Permeability of the material

μ0 = Absolute permeability = 4π x 10-7 H/m

μr = relative permeability 

Calculation:

Given-

I = 2350 A/m , B = 3.142 mWb/m2

B = μ0 (I + H)

\((I+H)=\frac{3.14\times10^{-3}}{4 \times 3.14\times10^{-7}}\)

H = 150

We know that,

B = μH

\(μ=\frac{3.14\times10^{-3}}{150}\)

μ = 20 x 10-6

The relative permeability of the material is

∵ μ = μ0μr 

\(μ_r=\frac{20\times10^{-6}}{4\times3.14\times10^{-7}}\)

μr ≈ 16.67

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