Correct Answer - Option 1 : 7,
\(\sqrt{69}\)
Concept:
If aî + bĵ + ck̂ and pî + qĵ + rk̂ are 2 different sides of the rhombus.
Suppose \(\vec{A} = aî + bĵ + ck̂\) and B = \(\vec{B}=pî + qĵ + rk̂\)
Then anyone diagonal of the rhombus is given by \(D_1=\vec{A}+\vec{B}\)
The other diagonal is given by \(D_2=\vec{B}-\vec{A}\)
The magnitude of the vector \(A=\sqrt{a^2+b^2+c^2}\)
Calculation:
Given:
2î + 4ĵ - 5k̂ and î + 2ĵ + 3k̂ are 2 different sides of rhombus.
Suppose, \(\vec{A} = 2î + 4ĵ - 5k̂\) and B = \(\vec{B}=1î + 2ĵ + 3k̂\)
Then anyone diagonal of the rhombus is given by \(D_1=\vec{A}+\vec{B}\)
\(D_1=\vec{A}+\vec{B}\)
D1 = (2î + 4ĵ - 5k̂) + (1î + 2ĵ + 3k̂)
D1 = 3î + 6ĵ - 2k̂
The magnitude of the vector diagonal D1
\(D_1=\sqrt{3^2+6^2+({-2})^2}\)
D1 = 7
The other diagonal is given by \(D_2=\vec{B}-\vec{A}\)
\(D_2=\vec{B}-\vec{A}\)
D2 = (1î + 2ĵ + 3k̂) - (2î + 4ĵ - 5k̂)
D2 = - 1î - 2ĵ + 8k̂
The magnitude of the vector diagonal D2
\(D_1=\sqrt{({-1})^2+({-2})^2+8^2}\)
\(D_1 =\sqrt{69} \)
∴ The length of diagonals of a rhombus is 7 and \(\sqrt{69} \).