Correct Answer - Option 1 : 18 Minutes
Given:
Pipe P can fill a tank in 5 minutes
Pipe Q can fill a tank in 4 minutes
Pipe R can empty a tank in 2 minutes
Calculation:
Pipe
|
Time
|
Total Work
= LCM (5, 4 and 2)
|
Efficiency(No. of units worked in a day)
|
P
|
5
|
|
20 ÷ 5 = 4
|
Q
|
4
|
20
|
20 ÷ 4 = 5
|
R
|
(2)
|
|
20 ÷ 2 = (10)
|
P+ Q + (-R)
|
|
|
4 + 5 -10 = (1)
Work done by all three pipes in a minute
|
⇒ Work done by (P + Q) in first 2 minutes = (4 + 5) × 2 = 18 units
⇒ Work done by (P+ Q – R) = 18/(1)
∴ R will take 18 minutes to empty the tank.
The Correct option is 1 i.e. 18 minutes.