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If ‘α’ and ‘β’ are the roots of expression px2 + qx + r = 0, then find the value of 2 (α2 + β2).
1. (2q2 + 4pr)/p2
2. (2q – 4r)/p
3. (2q2 – 4pr)/p2
4. (2q2 + pr)/p2

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Correct Answer - Option 3 : (2q2 – 4pr)/p2

GIVEN:

‘α’ and ‘β’ are the roots of expression px2 + qx + r = 0.

CONCEPT:

Algebra

CALCULATION:

Since ‘α’ and ‘β’ are the roots of expression px2 + qx + r = 0.

α + β = -q/p

αβ = r/p

Now,

(α – β)2 = (α + β)2 – 4αβ

(α – β)2 = (-q/p)2 – 4r/p

2 (α2 + β2) can be written as: 2α2 + 2β2 + 2αβ – 2αβ

= 2α2 + 2β2 + 2αβ – 2αβ

= α2 + β2 + 2αβ + α2 + β2 – 2αβ

= (α + β)2 + (α – β)2

= (-q/p)2 + (-q/p)2 – 4r/p

= q2/p2 + q2/p2 – 4pr/p2

= (2q2 – 4pr)/p2

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