Question

Take two marbles of m₁ , m₂ mass respectively. 

Make a collision in one second with marbles using u₁ , u₂ initial velocities respectively. 

Take the final velocities as v₁ , v₂ You observed the following in the experiment. 

m₁ = 10 kg u₁ = 5 m/s v₁ = 15 m/s 

m₂ = 100 kg u₂ = 2 m/s -v₂ = 1 m/s 

t = 1 sec 

Fill the table with suitable answers and write the conclusion from it.

	Marble 1	Marble 2
1. Momentum before collision
2. Momentum after collision
3. Change in momentum (∆p)
4. Rate of change in momentum \(\frac{\Delta p}{\Delta t}\)

Answer 1

	Marble 1	Marble 2
1. Momentum before collision	m1u1 =10 x 5 =50 m/s	m2u2 = 100 x 2 =200 m/s
2. Momentum after collision	m1v1 =10 x 15 =150 kg.m/s	m2v2 = 100 x1 =100 kg.m/s
3. Change in momentum (∆p)	m1v1 - m1u1=150 -50 = 100 kg.m/s	m2v2 - m2u2 = 100 - 200 =-100 kg.m/s
4. Rate of change in momentum \(\frac{\Delta p}{\Delta t}\)	\(\frac{(m_1v_1\,-\,m_1u_1)}{t} = \frac{100}{1} = 100 kg.m/s\)	\(\frac{-(m_2v_2\,-\,m_2u_2)}{t} = \frac{-(-100)}{1} = 100 kg.m/s\)

Conclusion : 

1. The table momentum is unchanged before and after collision. 

2. We can say that the momentum is conserved.