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Use Euclid division lemma to show that any positive odd integer is of the form 6q + 1 or 6q + 3 or 6q + 5, where q is some integers.

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Let ‘a’ be an odd positive integer. 

Let us now apply division algorithm with a and b = 6.

∵ 0 ≤ r < 6, the possible remainders are 0, 1, 2, 3, 4 and 5. 

i.e., ’a’ can be 6q or 6q + 1 or 6q + 2 or 6q + 3 or 6q + 4 or 6q + 5, where q is the quotient. 

But ‘a’ is taken as an odd number. 

∴ a can’t be 6q or 6q + 2 or 6q + 4. 

∴ Any odd integer is of the form 6q + 1, 6q + 3 or 6q + 5.

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