Data: e = 220 sin314.2t (in volt), t = \(\cfrac T4\)
(i) Comparing the given equation with e = e0 sin
ωt, we get, peak value, e0 = 220V.
(ii) erms = = e0/√ 2 = 155.6 V
(iii) eav (over half cycle) = \(\cfrac2{\pi}\)e0 = \(\cfrac{2(220)}{3.142}\) = 140 V
(iv) ω = 2πf= 314.2 ∴ The frequency,
f = \(\cfrac{ω}{2\pi}\) = \(\cfrac{314.2}{2(3.142)}\) = 50 Hz
(v) The period, T = \(\cfrac 1f\) = \(\cfrac 1{50}\) = 0.02 same
(vi) e = 220 sin \(\left(\cfrac{2\pi}T.{\cfrac T4}\right)\) = 220 sin \(\cfrac{\pi}2\) = 220 v