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For a given soil sample,

Cc = coefficient of gradation

Cu = coefficient of uniformity

D10 = effective size

D30 = diameter through which 30% of the total soil mass is passing

If Cc = 1.0 and Cu = 4.0, then what would be the value of D30/D10 ?


1. 2.00
2. 1.25
3. 1.50
4. 1.75

1 Answer

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Best answer
Correct Answer - Option 1 : 2.00

Given,

Cc = 1.0

Cu = 4.0

Coefficient of curvature (Cc):

\(C_c = \frac {D^2_{30}}{D_{60} × D_{10}}\)

Coefficient of uniformity (Cu):

\(C_u = \frac {D_{60}}{D_{10}}\)

D10 → effective size

D50 → average size

So,

\(C_c = \frac {D^2_{30}}{D_{60} × D_{10}}\)

Cc = 1

\(1 = \frac {D^2_{30}}{D_{60} × D_{10}}\)

D230 = D60 × D10     ...1)

and also given,

Cu = 4.0

\(\frac {D_{60}}{D_{10}} = 4\)

D60 = 4D10

Putting the value of D60 in equation 1)

D230 = 4D10 × D10

\(\left(\frac {D_{30}}{D_{10}}\right)^2 = 4\)

\(\frac {D_{30}}{D_{10}} = 2\)

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