Correct Answer - Option 1 : 2.00
Given,
Cc = 1.0
Cu = 4.0
Coefficient of curvature (Cc):
\(C_c = \frac {D^2_{30}}{D_{60} × D_{10}}\)
Coefficient of uniformity (Cu):
\(C_u = \frac {D_{60}}{D_{10}}\)
D10 → effective size
D50 → average size
So,
\(C_c = \frac {D^2_{30}}{D_{60} × D_{10}}\)
Cc = 1
\(1 = \frac {D^2_{30}}{D_{60} × D_{10}}\)
D230 = D60 × D10 ...1)
and also given,
Cu = 4.0
\(\frac {D_{60}}{D_{10}} = 4\)
D60 = 4D10
Putting the value of D60 in equation 1)
D230 = 4D10 × D10
\(\left(\frac {D_{30}}{D_{10}}\right)^2 = 4\)
\(\frac {D_{30}}{D_{10}} = 2\)