Correct Answer - Option 3 : 20 years
Given :
A sum double itself in 10 years
Formula used :
\(Amount = P(1+R/100)^n\)
2P = P (1+r%/100) 10 eq 1
4P = P (1+r%/100) n eq 2
Divide wq 2 / 1
\(\frac{4}{2} = \frac{{{{\left( {1 + r/100} \right)}^n}}}{{\begin{array}{*{20}{c}} {{{\left( {1 + \frac{r}{{100}}} \right)}^{10}}}\\ {} \end{array}}}\)
2 × (1 +r/100)10 = (1 +r/100)n
(1 +r/100)20 = (1 +r/100)n
N = 20 years