Question

Loss of head at Exit of pipe is calculated by - 
1. \(0.375 \dfrac{v^2}{2g}\)
2. \(0.5\dfrac{v^2}{2g}\)
3. \(0.25\dfrac{v^2}{2g}\)
4. \(\dfrac{v^2}{2g}\)

Answer 1

Correct Answer - Option 4 : \(\dfrac{v^2}{2g}\)

Minor head losses:

• Head loss at entry
  • \({h_{Le}} = \frac{{{{0.5{{V_1}}}^2}}}{2g}\)
• Head loss due to expansion
  • \({h_{Le}} = \frac{{{{\left( {{V_1} - {V_2}} \right)}^2}}}{2g}\)
• Head loss at exit
  • \({h_{Le}} = \frac{{{V^2}}}{{2g}}\)